The quantity of charge that will be transferred by a current flow of 10 A over 1 hour period is
a. 10 C
b. 36000 C
c. 2400 C
d. 160 C
Answer:
t= 1 hr = 3600 sec
Q=I*t = 10*1*3600 = 36000 coulombs
a. 10 C
b. 36000 C
c. 2400 C
d. 160 C
Answer:
t= 1 hr = 3600 sec
Q=I*t = 10*1*3600 = 36000 coulombs
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